((+/) % #) &. ^. is the same as (+/ % #) &. ^. because adverb (/ in this case) b... | Hacker News

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		avmich on Dec 25, 2017 \| parent \| context \| favorite \| on: A different view on Functional Programming ((+/) % #) &. ^. is the same as (+/ % #) &. ^. because adverb (/ in this case) binds with + before three verbs +/ , % and # are grouped into the fork. So some parentheses aren't necessary. It would be cleaner to show three expressions which share the common part as similar in letters as well.

tiborsaas on Dec 25, 2017 | [–]

Is this software? What does it do?

wvlia5 on Dec 25, 2017 | [–]

Thanks, fixing it

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