well, probably. it likely depends on how the move works; muxes aren't free and driving long wires isn't either

but the confusion in the comment you are replying to is that it thinks you are deriving a floating-point matrix multiply algorithm, when in fact you are deriving an integer matrix multiply algorithm

floating-point adds are slightly more expensive than floating-point multiplies

integer multiplies are enormously more expensive than integer adds (in power and area, though not in time)